PLEASE HELP WILL FAN AND MEDAL Which are The rational roots for f(x)=5x^2-3x+3 A +/-1 B +/-3 C +/-1/3 D +/-5 E +/-1/5
Choose all correct answers
Just by seeing that the discriminant is < 0 it is apparent that there are no real solutions. All of the solutions you propose are real.
As NoelGreco said, there are no real solutions to that equation, so none of those options are correct. a = 5 b = -3 c = 3, so if you were to plug a,b,c into the quadratic formula it wouldn't work because the discriminant (the b^2 - 4ac in the quadratic formula: what is under the root sign) cannot be negative... since you can't take the square root of a negative number and get a real solution. b^2 - 4ac = = (-3)^2 - 4(5)(3) = 9 - 60 = (-) The discrimant is negative in this case so there are no real solutions.
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