Question

Did I solve this correctly? Implicit Differentiation ^_^

Answer 1

\[3x^2-xy^3=6x\]

Answer 2

yes

Answer 3

i think

Answer 4

\[6x-y^3-3y^2*\frac{dy}{dx}*x=6\]

Answer 5

lol another county heard from

Answer 6

hi sat 73

Answer 7

I get \[\frac{dy}{dx}= \frac{-6-6x+y^3}{-3y*x}\]

Answer 8

a medal for you

Answer 9

yea just for future reference it is a lot easier to write
\[6x-y^3-3xy^2y'=6\]

Answer 10

oh ok thanks yeah such a time saver ^_^

Answer 11

yeah especially here
not sure about your algebra though

Answer 12

maybe just a typo
denominator should be \(-3xy^2\) you are missing the exponent on the y

Answer 13

oops yeah hehe

Answer 14

Thank you :)

Answer 15

yw
i would also get rid of some of those minus signs, but that is just my preference, makes no difference

Answer 16

how?

Answer 17

\[\frac{dy}{dx}= \frac{-6-6x+y^3}{-3y^2x}\]\[=\frac{6+6x-y^3}{2xy^2}\]

Answer 18

but like i said, makes no difference

Answer 19

the numerator looks a little off

Answer 20

oops caught again

Answer 21

oy, the \(6\) on the right is not negative

Answer 22

\[\frac{dy}{dx}= \frac{6-6x+y^3}{-3xy^2}\]

Answer 23

@Zarkon always keeps me honest

Answer 24

cool thanks :)

Answer 25

now i have a question
what do you sell on ebay?