Question

help!

Simplify. write without negative exponent.
1) (3x)^2(x)^-5
2)(-5x)^0
3) (-7x)^-2
4)(a^6b^5/10a^3)^3
5)(-20d^4/5b^3)^3

Answer 1

Well for the first one 3x^2 remains on top

x^-5 is just 1/x^5

so, you're left with

(3x)^2 / x^5

= 9/x^3

Do you understand all those steps?

Answer 2

Yeah, sort of @blurbendy

Answer 3

what dont you get

Answer 4

how did you get the x^3? @blurbendy

Answer 5

if you have something that's like

x^2 / x^4 it's just

1 / x^2

the x'2s on top canceled with two of them on the bottom

Answer 6

Can you help me with the rest of them? @blurbendy

Answer 7

the second one is easy. anything to the ^0 power is always 1

Answer 8

try number 3, what do you think?

Answer 9

I have no clue, when I use a calculator I get a decimal

Answer 10

@blurbendy

Answer 11

you dont need a calculator. just look at the first example. what happens if something is raised to a negative power?

Answer 12

It's basically the opposite of the negative, so it will be positive? @blurbendy

Answer 13

the exponent will be. you end up with

1 / (-7x)^2

= 1 / 49x^2

Answer 14

How would you do 4 and 5 they are fractions and have a few more exponents than the other ones? @blurbendy

Answer 15

you're left with a^3 on top, because 3 of them cancel with the a^3 on the bottom. then just raise everything to the third power

(a^27b^15/1000)

Answer 16

where did you get the 27 from? @blurbendy

Answer 17

(a^3)^3 = a^27

Answer 18

Oh, okay. Now what about 5? @blurbendy

Answer 19

first divide 20 by 5 = 4

then cube everything

= -64b^9d^12