The graph of y=|x| is reflected in the x-axis and then moved 1 unit to the left and 3 units up. Write an equation of the new function.
okay, here are some rules, SHIFTS from \(\large\color{black}{ f(x) }\) to form \(\large\color{black}{ g(x) }\). \(\large\color{black}{ f(x)=\left| x \right| ~~~~~\bf{\rightarrow}~~~~~g(x)=\left| x \color{blue}{ -~\rm{c} }\right| }\) \(\large\color{blue}{ ~\rm{c} }\) units to the right. \(\large\color{black}{ f(x)=\left| x \right| ~~~~~\bf{\rightarrow}~~~~~g(x)=\left| x \color{blue}{ +~\rm{c} }\right| }\) \(\large\color{blue}{ ~\rm{c} }\) units to the left. \(\large\color{black}{ f(x)=\left| x \right| ~~~~~\bf{\rightarrow}~~~~~g(x)=\left| x \right| \color{blue}{ +~\rm{c} }}\) \(\large\color{blue}{ ~\rm{c} }\) units to up. \(\large\color{black}{ f(x)=\left| x \right| ~~~~~\bf{\rightarrow}~~~~~g(x)=\left| x \right| \color{blue}{ -~\rm{c} }}\) \(\large\color{blue}{ ~\rm{c} }\) units to down.
when you reflect over the x axis u are ultimately making your y negative
the reflection across x-axis, \(\large\color{black}{ f(x)=\left| x \right| ~~~~~\bf{\rightarrow}~~~~~g(x)=\color{blue}{ ~\rm{-} }\left| x \right| }\)
So you get it?
Yes thank you!!
can you write or draw your new equation (just in case, you don't have to) ?
\[y=-\left| x+1 \right|+3\]
YES !!
thank you!!
beautiful, and with latex, \(\huge\color{ blue }{\huge {\bbox[5pt, cyan ,border:2px solid purple ]{ \large\color{black}{ y=\color{red}{ ~\rm{- }} \left| x \color{blue}{ ~\rm{+~1} }\right|\color{green}{ ~\rm{+~3} }} }}}\)
like this, \(\huge\color{ blue }{\huge {\bbox[5pt, lightcyan ,border:2px solid red ]{ \large\color{black}{ y=\color{red}{ ~\rm{- }} \left| x \color{blue}{ ~\rm{+~1} }\right|\color{green}{ ~\rm{+~3} }} }}}\)
Anyways..... good luck with your math:) You welcome!
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