Question

sin2x=cosx

Answer 1

What are you trying to say/ask?

Answer 2

oops sorry sin2x=cosx solve for x with 0 to 2pi restriction

Answer 3

Oh, sorry. I haven't yet learned that stuff.

Answer 4

is it
\[\sin(2x)=\cos(x)\]?

Answer 5

yeah

Answer 6

use the "double angle" formula on the left first

Answer 7

solve
\[2\sin(x)\cos(x)=\cos(x)\] subtract cosine, factor etc

Answer 8

wait oops im sorry its sin(3x) = cos(3x) my badd

Answer 9

sine and cosine are equal at \(\frac{\pi}{4}\) where they are both \(\frac{\sqrt2}{2}\) and also at \(\frac{5\pi}{4}\) where they are both \(-\frac{\sqrt2}{2}\)

Answer 10

hehehehehe get rekt satellite

Answer 11

aren't there more answers though

Answer 12

since its from 0 to 2pi

Answer 13

could be

Answer 14

keep going around the circle

Answer 15

wait would this be correct

divide cos3x to get

sin3x/cos3x = 1

Answer 16

so it would be tan3x = 1

Answer 17

then inverse tan to get 3x = tan -1(1)

Answer 18

so 3x = pi/4 and 5pi/4