Find the Projection of v onto u where u=(2/3)i-(2/3)j-(1/3)k and v=2i-2j+2k
The projection of a vector \(\vec{a}\) onto another vector \(\vec{b}\) is given by \[\|a\|\cos\theta\times\frac{\vec{b}}{\|\vec{b}\|}\] where \(\theta\) is the angle between the vectors. Recall that \[\vec{a}\cdot\vec{b}=\|a\|\|b\|\cos\theta~~\iff~~\cos\theta=\frac{\vec{a}\cdot\vec{b}}{\|a\|\|b\|}\]
All this means you need to find the dot product of the given vectors along with the norms of each vector.
Would the opposite also be true?
projection of B onto A
By "opposite" you must mean switch \(a\) with \(b\) in the formulas above? Then yes. The projection of \(b\) onto \(a\) would be \(\|\vec{b}\|\cos\theta\dfrac{\vec{a}}{\|\vec{a}\|}\).
\[\theta=\cos^{-1} \frac{ UV \ }{ \left| UV \right|^2 }V\]
oh alright thank you
yw
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