What is the equation in point-slope form of the line passing through (0, 5) and (−2, 11)?

Question

anonymous · Answer

Firstly find the slope :
$$Slope = \frac{y_2 - y_1}{x_2 - x_1}$$

anonymous · Answer

$x_1 = 0,\  y_1 = 5,\  x_2 = -2, \ y_2 = 11$

anonymous · Answer

-3

anonymous · Answer

So, it looks good to me.. :)

anonymous · Answer

$$Slope = \frac{11-5}{-2} = -3$$

anonymous · Answer

Now, equation in point-slope form is given as :
$y = mx + b$, where $m$ is the slope and $b$ is y-intercept, Right?

anonymous · Answer

$m$ we have found as $-3$ just now..
So, let us put it in that equation.

anonymous · Answer

$y = -3x + b$
Now, we need to find $b$..

anonymous · Answer

Just substitute any one point in that equation, because, if line passes through $(0,5)$, then this point must satisfy the equation : So put : $x=0, \ y = 5$ in that equation and find $b$..

anonymous · Answer

When you put $x=0$ and $y=5$, in $y = -3x + b$, then what the value of $b$ you will get?

anonymous · Answer

8?