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Mathematics 17 Online
OpenStudy (anonymous):

If a is real, what is the only real number that could be a miltiple root of x^3+ax+1=0

OpenStudy (anonymous):

Maybe think about it like a quadratic equation? \[ x(x^2)+a(x) + 1=0 \]

OpenStudy (anonymous):

I dunno, I'm grasping at straws.

OpenStudy (anonymous):

i tried that but didn't have much luck! the whole "real" thing in the question doesn't seem much of a help

OpenStudy (freckles):

what does that mean "the only real number that could be a multiple root of ..."

OpenStudy (freckles):

like a root with multiplicity 2?

OpenStudy (freckles):

or even multiplicity 3

OpenStudy (anonymous):

i wrote the whole question as it was, maybe they mean like \[\pm2\]

OpenStudy (freckles):

say x=k is a zero (with multiplicty 2) f(k)=0 that is k^3+ak+1=0 so if we see what (x^3+ax+1)/(x-k) is we get|dw:1417674731678:dw|

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