can some help me with this, I'm confuse

if two household are independently selected, what is the probability that both have income in the $30,000- $39,999 range?

Income
0- $9,999 6%
$10,000-$19,999 9%
$20,000- 29,999 13%
$30,000-$39,999 28%
$40,000-$49,999 18%
$50,000-$59,999 17%
$60,000 or more 9%

Question

can some help me with this, I'm confuse

if two household are independently selected, what is the probability that both have income in the $30,000- $39,999 range?

Income
0- $9,999                6%
$10,000-$19,999    9%
$20,000- 29,999     13%
$30,000-$39,999    28%
$40,000-$49,999    18%
$50,000-$59,999   17%
$60,000 or more       9%

kropot72 · Answer

Let the event that one household has income in the $30,000- $39,999 range be A.
P(A) = 0.28
Let the event that the other household has income in the $30,000- $39,999 range be B.
P(B) = 0.28
It is given that the selections are made independently. Therefore the probability that both households have income in the $30,000- $39,999 range is given by:
$$\large P(A \cap B)=P(A) \times P(B)=0.28\times0.28=you\ can\ calculate$$