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Chemistry 8 Online
OpenStudy (anonymous):

How exactly do you get this result? (moles and particles)

OpenStudy (anonymous):

I have been trying to figure this out. I am looking at some chemistry examples but I cannot get how they got that result. This wasn't explained.

OpenStudy (anonymous):

If you have 1.50 moles of ammonia (NH3), how many atoms of hydrogen do you have?

OpenStudy (anonymous):

1.50 Moles x 6.022 x 10^23/1 mole = 9.03 * 10^23

OpenStudy (anonymous):

I get this so far, but this is where I get confused

OpenStudy (anonymous):

3 x (9.03 * 10^23 particles) = 2.71 * 10^24

OpenStudy (anonymous):

How did they get to this last entry?

OpenStudy (jfraser):

the formula of ammonia tells you that you have ONE nitrogen atom and THREE hydrogen atoms (PER MOLECULE)

OpenStudy (jfraser):

so one mole of ammonia MOLECULES contains THREE MOLES of hydrogen atoms

OpenStudy (anonymous):

Yes I get all of that. However, what I'm stuck on is that I used simple math to calculate what: 3 * (9.03 * 10^23 particles) would be, but it just doesn't equal: (2.71 * 10^24)

OpenStudy (jfraser):

i don't know where you're confused, because it does

OpenStudy (anonymous):

Can you tell me how to do it just in case I am missing a step?

OpenStudy (jfraser):

3 * 9.03 = 27.09 (or 27.1)

OpenStudy (jfraser):

add in the scientific power and you get \[27.1*10^{23}\]

OpenStudy (anonymous):

See mine says 27.1 * 10^24

OpenStudy (anonymous):

an extra zero

OpenStudy (jfraser):

no, it says \(2.71*10^{24}\), which is equal to \(27.1*10^{23}\)

OpenStudy (anonymous):

27.1 * 10^24 is what this example says

OpenStudy (jfraser):

then the example is off by a power of 10

OpenStudy (anonymous):

No really, this example says 27.1

OpenStudy (anonymous):

They must've made a mistake

OpenStudy (jfraser):

then it's wrong

OpenStudy (anonymous):

Well thanks anyways for clearing this up

OpenStudy (anonymous):

Yeah. Thanks again

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