How do I solve this?
\[\huge 3^{b}=7\]
3 times wat = 7 it will b a decimal
6.1
Study
im acally not sure
NEVER EVER
Give the direct answer
now that i think about it it is 6.1
No no it's definitely 6.1. I know it. I know because I solved the math out.
you have to make use of logarithms here.
Take Logs both the sides, take Log to the base 10, generally we take this.. If the base is 10, then need not to mention it..
\[\log(3)^b = \log(7)\]
See, I have not mention base there, so it is understood as 10, okay??
Okay. Now what do I do next?
\[\log(a)^n = n \cdot \log(a)\]
Power comes down in multiplication, getting?
If getting, then make use of it there..
Wait who are you talking to? Me or someone invisisble?
*invisible
He or she knows.. Why you care??
No offense though . . .
Is it supposed to be \[\log(a)^n = n \cdot \log(a)\] or \[\log(a)^n = n \cdot \log(b)\]
That was just the formula I gave..
The formula says : \[\log(a)^n = n \cdot \log(a)\]
\(a=3\) and \(n=b\)..
\[\log(\color{red}{3})^{\color{blue}{b}} = \log(7) \\ \implies \color{blue}{b} \cdot \log(\color{red}{3}) = \log(7)\]
getting this?
No idea what the heck you're talking about. Really.
Is your computer okay?? @ComicPicLoyalty
Yeah. Why?
Is YOURS okay @waterineyes ?
@ComicPicLoyalty can't you see that Rosedryer has asked this question?
RoseDryer asked this same question? I don't believe you.
And may I ask what RoseDryer asked?
Look above, you will get it..
So we have \[\log(\color{red}{3})^{\color{blue}{b}} = \log(7) \\ \implies \color{blue}{b} \cdot \log(\color{red}{3}) = \log(7)\] Sorry for late reply. Baby was crying.
Do you have calculator with you?
Oh my God who are you talking to? You're confusing me! Ugh. . . . you makin things so difficult (ew ew) lookin at her hair hair hair (ew ew ew) i don't like her hair at all because she things she gets them fall she makes herself fall on the ground and then everyone is laughing at her . . . Hey Red carpet, you can shake it out of my pocket . . . i don't wanna be obnoxious but she looks like she from Gothic . . .
Divide by \(\log(3)\) both the sides: \[b = \frac{\log(7)}{\log(3)}\]..
Calculate \(\log(7)\) and \(\log(3)\) with that calculator. And then divide them, you will get the value of \(b\)..
Sorry openstudy is lagging bag. Nothing was popping up Oh okay thank you!
I got b = 1.77124374916
bad*
Yeah that is right..
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