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Mathematics 20 Online
OpenStudy (anonymous):

How do I solve this?

OpenStudy (anonymous):

\[\huge 3^{b}=7\]

OpenStudy (anonymous):

3 times wat = 7 it will b a decimal

OpenStudy (anonymous):

6.1

OpenStudy (anonymous):

Study

OpenStudy (anonymous):

im acally not sure

OpenStudy (anonymous):

NEVER EVER

OpenStudy (anonymous):

Give the direct answer

OpenStudy (anonymous):

now that i think about it it is 6.1

OpenStudy (anonymous):

No no it's definitely 6.1. I know it. I know because I solved the math out.

OpenStudy (anonymous):

you have to make use of logarithms here.

OpenStudy (anonymous):

Take Logs both the sides, take Log to the base 10, generally we take this.. If the base is 10, then need not to mention it..

OpenStudy (anonymous):

\[\log(3)^b = \log(7)\]

OpenStudy (anonymous):

See, I have not mention base there, so it is understood as 10, okay??

OpenStudy (anonymous):

Okay. Now what do I do next?

OpenStudy (anonymous):

\[\log(a)^n = n \cdot \log(a)\]

OpenStudy (anonymous):

Power comes down in multiplication, getting?

OpenStudy (anonymous):

If getting, then make use of it there..

OpenStudy (anonymous):

Wait who are you talking to? Me or someone invisisble?

OpenStudy (anonymous):

*invisible

OpenStudy (anonymous):

He or she knows.. Why you care??

OpenStudy (anonymous):

No offense though . . .

OpenStudy (anonymous):

Is it supposed to be \[\log(a)^n = n \cdot \log(a)\] or \[\log(a)^n = n \cdot \log(b)\]

OpenStudy (anonymous):

That was just the formula I gave..

OpenStudy (anonymous):

The formula says : \[\log(a)^n = n \cdot \log(a)\]

OpenStudy (anonymous):

\(a=3\) and \(n=b\)..

OpenStudy (anonymous):

\[\log(\color{red}{3})^{\color{blue}{b}} = \log(7) \\ \implies \color{blue}{b} \cdot \log(\color{red}{3}) = \log(7)\]

OpenStudy (anonymous):

getting this?

OpenStudy (anonymous):

No idea what the heck you're talking about. Really.

OpenStudy (anonymous):

Is your computer okay?? @ComicPicLoyalty

OpenStudy (anonymous):

Yeah. Why?

OpenStudy (anonymous):

Is YOURS okay @waterineyes ?

OpenStudy (anonymous):

@ComicPicLoyalty can't you see that Rosedryer has asked this question?

OpenStudy (anonymous):

RoseDryer asked this same question? I don't believe you.

OpenStudy (anonymous):

And may I ask what RoseDryer asked?

OpenStudy (anonymous):

Look above, you will get it..

OpenStudy (anonymous):

So we have \[\log(\color{red}{3})^{\color{blue}{b}} = \log(7) \\ \implies \color{blue}{b} \cdot \log(\color{red}{3}) = \log(7)\] Sorry for late reply. Baby was crying.

OpenStudy (anonymous):

Do you have calculator with you?

OpenStudy (anonymous):

Oh my God who are you talking to? You're confusing me! Ugh. . . . you makin things so difficult (ew ew) lookin at her hair hair hair (ew ew ew) i don't like her hair at all because she things she gets them fall she makes herself fall on the ground and then everyone is laughing at her . . . Hey Red carpet, you can shake it out of my pocket . . . i don't wanna be obnoxious but she looks like she from Gothic . . .

OpenStudy (anonymous):

Divide by \(\log(3)\) both the sides: \[b = \frac{\log(7)}{\log(3)}\]..

OpenStudy (anonymous):

http://web2.0calc.com/

OpenStudy (anonymous):

Calculate \(\log(7)\) and \(\log(3)\) with that calculator. And then divide them, you will get the value of \(b\)..

OpenStudy (anonymous):

Sorry openstudy is lagging bag. Nothing was popping up Oh okay thank you!

OpenStudy (anonymous):

I got b = 1.77124374916

OpenStudy (anonymous):

bad*

OpenStudy (anonymous):

Yeah that is right..

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