WHich is the graph of y= 1/2x?
A. http://static.k12.com/calms_media/media/1503500_1504000/1503772/1/5afd0b9bb4861bae518958d61ebaa2a6f9dddcc4/MS_IMC-140523-131303.jpg B. http://static.k12.com/calms_media/media/1503500_1504000/1503783/1/17761cebebae1d8538053aa11c62dfbf6c7f794f/MS_IMC-140523-1313019.jpg C. http://static.k12.com/calms_media/media/1503500_1504000/1503782/1/a2a4fea3c53d2a02f140780631b06aef06c794c4/MS_IMC-140523-1313013.jpg D. http://static.k12.com/calms_media/media/1503500_1504000/1503781/1/24c8ee5bb5a616ae73b02f06225d167c50b337f3/MS_IMC-140523-1313012.jpg
\[\large \rm y = \dfrac{1}{2}x\]
probably graph A bye
a
yeah i was thinking A 2
thats a very good wrong guess
its c
realy?
slope = 1/2 rise = 1 run = 2
Its C
that means the graphs goes UP 1 unit for every 2 units RIGHT yes ?
y = (1/2)^x is an exponential function where x is the exponent 1° case when x approaches negative infinity Note that y = (1/2)^x = 2^(-x) so when x -> (-inf.), function approaches y = 2^[-(-inf)] = 2^(+inf) and lim(y) {x -> -inf} = +inf When x decreases to -inf., y grows to +inf 2° case when x approaches positive infinity We can write y = (1/2)^x = f(x)/g(x) where f(x)=1 and g(x)=2^x and then use following rule lim[f(x)/g(x)] {x -> inf} = lim f(x) {x -> inf} / lim g(x) {x -> inf} therefore lim[(1/2)^x] {x -> inf} = lim[1/(2^x)] {x -> inf} = lim (1){x -> inf} / lim (2^x){x -> inf} lim (1){x -> inf} = 1 lim (2^x){x -> inf} = inf lim[(1/2)^x] {x -> inf} = 1 / inf. = 0 The limit of y as x approaches +infinity is 0. That means horizontal line y=0 is horizontal asymptote of function y = (1/2)^x. 3° intercept with y-axis For x=0, y = (1/2)^0 = 1 Graph of this function passes through (0,1).
thats a different question y = (1/2)x is not same as y = (1/2)^x
btw C is the right graph
im not sure its C
i would have to go with a
because theres a direct split in graph A
A is y = 2x @some.random.cool.kid
im confused
@ganeshie8 the right answer is C
yes
thx
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