Factor 30 - 5y
5(6-y)
We can't do much here, but the thing we can do is take "common factor". "Common factor" is a reverse step from the distributive axiom in arithmetics, wich states that if a number multiplies the sum of other two, it's the same as the sum of each number multiplicating the outside individually, visually written like this: \[a(b+c)=ab+ac\] So therefore, "common factor" would be more a, "if the operation of two or more numbers wich have a multiple in common, it's the same as the multiple multiplying the sum of the both numbers divided by the multiple" more visually: \[a.c \pm a.b=a(c \pm b)\] so, for the problem in question: 30-5y We can clearly see that 5 actually is a multiple of 30, so all I do is take it as common factor, and divide both numbers by 5: \[30-5y=5(\frac{ 30 }{ 5 }-\frac{ 5y }{ 5 })\] 30/5=6 and 5/5=1, therefore: \[30-5y=5(6-y)\] so we conclude that it's factored form is: \[5(6-y)\]
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