Prove: csc(2A)+cot(2A)=cot(A)
double angles, or second powers?
Kelly, your 2s seem ambiguous. where is the 2nd power, where is a double angle? if it is a double angle, put (2x) in parenthesis, it if is a power of 2, put a caret (^ symbol) next ti the x.
They are double angles
\(\large\color{black}{ \csc(2a)+\cot(2a)=\cot(a) }\)
\(\large\color{black}{ \frac{1}{2\sin(a)\cos(a)}+\frac{\cos^2(x)-\sin^2(x)}{2\sin(a)\cos(a)}=\cot(a) }\)
\(\large\color{black}{ \frac{1+\cos^2(x)-\sin^2(x)}{2\sin(a)\cos(a)}=\cot(a) }\)
\(\large\color{black}{ \frac{2\cos^2(x)}{2\sin(a)\cos(a)}=\cot(a) }\)
\(\large\color{black}{ \frac{\cos(a)}{\sin(a)}=\cot(a) }\)
In my process whenever I said x, ignore that and regard it as a.
apologize for my mistake, to write x and not a... I am so used to an angle of x.
Thank you!
anytime... and if you have a question about any of the steps, ask.
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