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OpenStudy (anonymous):
Prove: csc(2A)+cot(2A)=cot(A)
11 years ago
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OpenStudy (anonymous):
double angles, or second powers?
11 years ago
OpenStudy (anonymous):
Kelly, your 2s seem ambiguous. where is the 2nd power, where is a double angle?
if it is a double angle, put (2x) in parenthesis, it if is a power of 2, put a caret (^ symbol) next ti the x.
11 years ago
OpenStudy (anonymous):
They are double angles
11 years ago
OpenStudy (anonymous):
\(\large\color{black}{ \csc(2a)+\cot(2a)=\cot(a) }\)
11 years ago
OpenStudy (anonymous):
\(\large\color{black}{ \frac{1}{2\sin(a)\cos(a)}+\frac{\cos^2(x)-\sin^2(x)}{2\sin(a)\cos(a)}=\cot(a) }\)
11 years ago
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OpenStudy (anonymous):
\(\large\color{black}{ \frac{1+\cos^2(x)-\sin^2(x)}{2\sin(a)\cos(a)}=\cot(a) }\)
11 years ago
OpenStudy (anonymous):
\(\large\color{black}{ \frac{2\cos^2(x)}{2\sin(a)\cos(a)}=\cot(a) }\)
11 years ago
OpenStudy (anonymous):
\(\large\color{black}{ \frac{\cos(a)}{\sin(a)}=\cot(a) }\)
11 years ago
OpenStudy (anonymous):
In my process whenever I said x, ignore that and regard it as a.
11 years ago
OpenStudy (anonymous):
apologize for my mistake, to write x and not a... I am so used to an angle of x.
11 years ago
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OpenStudy (anonymous):
Thank you!
11 years ago
OpenStudy (anonymous):
anytime... and if you have a question about any of the steps, ask.
11 years ago
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