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OpenStudy (anonymous):

John’s age is three times that of Alan’s. Ralph’s age is twice that of Alan’s. What is the ratio of John’s age to Ralph’s? 6:1 2:3 3:2 1:6

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

What is the ratio of John's age to Alan's age?

OpenStudy (anonymous):

They don't give anyone's age. That's the confusing part.

OpenStudy (anonymous):

I would say 3:2

OpenStudy (anonymous):

It doesn't matter, ratios don't require specific numbers, they simply give relations between two numbers. If box A is twice as big as box B, then the ratio of their sizes is 2:1. Can you now tell me what the ratio of John's age to Alan's age is?

OpenStudy (anonymous):

3:1

OpenStudy (anonymous):

@Tom982 It doesn't tell me. Everything I posted above is all the information they give me.

OpenStudy (anonymous):

I think you're misunderstanding me. You're given that "John’s age is three times that of Alan’s", so what is the ratio between the two ages?

OpenStudy (anonymous):

@tom982 Wouldn't it be 3:1? Since John's age is 3 time Alan's 1? :/

OpenStudy (anonymous):

Exactly!

OpenStudy (anonymous):

Now what is the ratio of Ralph to Alan?

OpenStudy (anonymous):

Would it be 2:1?

OpenStudy (anonymous):

@tom982

OpenStudy (anonymous):

Or would it be 2:3? :/

OpenStudy (anonymous):

Exactly, so J:A = 3:1, and R:A = 2:1. So J:R = 3:2. You could look at this another way, if it helps you understand. We know J=3A and R=2A, now find J in terms of R and write it as a ratio: A=0.5R J=3A=3(0.5R)=1.5R 2J=3R which is equivalent to saying J:R = 3:2.

OpenStudy (anonymous):

Thanks Tom I understand now! :)

OpenStudy (anonymous):

No problem! Glad you understand.

OpenStudy (anonymous):

tom you are great at explaining things! (I am too but I lack the patience)

OpenStudy (anonymous):

@tom982 A neutron star has a density of about 5.9 10 17 kg/m3. What would be the approximate mass of a 1-centimeter cube (a cube 1 cm on all sides)? 5.9 10^14 kg (1300 trillion pounds) 5.9 10^8 kg (1.3 billion pounds) 5.9 10^17 kg (1.3 quadrillion pounds) 5.9 10^11 kg (1.3 trillion pounds) In a recent census, New York City had a population of 8,336,697 people, and an area of 302.64 square miles, while London had a population of 3,792,621, and an area of 469 square miles. (No choices) What are the population densities (to the nearest person) of the two cities? New York: London: A road map has a scale of 10 miles per inch. The length of the straight-line road on the map between two cities is 6 inches. If the road between the cities has a speed limit of 30 mph, about how long should it take to drive from one city to the next? 2 hours 4 hours 1 hour 3 hours A scale model of an office building is 3' x 2' x 5' (length, width, height). If the actual building has a length of 45 feet, what is the volume of the actual building? 81,000 cubic feet 102,150 cubic feet 101,250 cubic feet 30,000 cubic feet

OpenStudy (anonymous):

Okay let's work through these part by part, starting with the neutron star.

OpenStudy (anonymous):

OK!

OpenStudy (anonymous):

We know the weight is 5.91017 kgm^{-3} and we want the weight of a 1cm cube, so we can either convert the weight into kgcm^-3 or convert the 1cm cube into m^3. Take your pick!

OpenStudy (anonymous):

Convert the 1cm cube to m^3

OpenStudy (anonymous):

Okay, so what's 1cm^3 in m^3?

OpenStudy (anonymous):

Sorry I'm not too sure how to convert it. :(

OpenStudy (anonymous):

Okay, no worries. What's 1cm in m?

OpenStudy (anonymous):

Would it be 1.0 × 10-6 m^3

OpenStudy (anonymous):

0.01

OpenStudy (anonymous):

0.01 is correct :) So there's 0.01cm in a m, and 0.01^2 cm^2 in m^2, so how many cm^3 are in a m^3?

OpenStudy (anonymous):

umm... 1,000,000cm3? Sorry if it's wrong, i'm really bad at math.

OpenStudy (anonymous):

No you're not, that last question couldn't be more wrong if I tried, sorry about that. You're perfectly right, but what I meant to ask was how many m^3 in cm^3 which is 1/1000000=0.0000001. So we know our 1cm^3 cube is 0.0000001m^3, and we know a neutron star weighs 5.91017 kg per cubic metre, so what's the weight of our cube?

OpenStudy (anonymous):

1,300 trillion pounds? The first answer choice?

OpenStudy (anonymous):

I have one too many zeroes in my previous post, it should be: 0.000001.

OpenStudy (anonymous):

And is your question meant to say 5.9x10^17? Because all I see is 5.9 10 17.

OpenStudy (anonymous):

0.000001*5.9x10^17=5.9x10^11

OpenStudy (anonymous):

Oh so it would be the last one. for the first one. :)

OpenStudy (anonymous):

Exactly

OpenStudy (anonymous):

Now for the second one!

OpenStudy (anonymous):

Divide the number of people by the number of square miles to find the people per square mile for each of them (round accordingly) :)

OpenStudy (anonymous):

So NYC: 27546.5800952 London: 8086.6119403

OpenStudy (anonymous):

@tom982

OpenStudy (anonymous):

Rounded it would be NYC: 27,546.58 London: 8,086.61 Right?

OpenStudy (anonymous):

Close, can you have 0.58 of a person?

OpenStudy (anonymous):

No. So would I just remove the decimal entirely?

OpenStudy (anonymous):

Yeah, well, round it: "What are the population densities (to the nearest person) of the two cities?"

OpenStudy (anonymous):

@tom982 I already rounded from hundredths place and that's how I got those results. If I remove the decimal it would be 27,546 and 8,086. Is that correct?

OpenStudy (anonymous):

You're not rounding from hundredths, you're rounding to the nearest whole number.

OpenStudy (anonymous):

NYC: 27,547 London: 8,087

OpenStudy (anonymous):

Yep, spot on

OpenStudy (anonymous):

Yay! Third problem. :)

OpenStudy (anonymous):

10 miles per inch. So 6 inches is how many miles? Then at 30mph, how long would it take to drive that distance?

OpenStudy (anonymous):

@tom982 1 hour?

OpenStudy (anonymous):

No, we know 6 inches is 60 miles and at 30 miles per hour, this would take 2 hours.

OpenStudy (anonymous):

I'm sorry it should be 2 hours, right? Every 10 miles you're going an inch, so in 6 inches you're going 60 miles. You then do 30/60 which is 2.

OpenStudy (anonymous):

Yeah, but your last fraction is upside down :)

OpenStudy (anonymous):

Oh lol, thanks!

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