*simplify the following expression*
(\[(3y ^{2}-4y+2) + (4y ^{2}+4y-7)\]
@Jhannybean
5Y^2+-5
This can be done while ignoring the parenthesis, Since it is all subtraction and addition. Subtraction and additiion can be done in any order. I would recommend combining all like terms which would mean 3y^2+4y^2; as well as -4y+4y Let me know what you end up with after you combine all like terms
\[7y ^{2}-5\]
Correct. -4y+4y is equal to 0. But you leave the 0 out of the equation.
And -5 comes from adding positive 2 to negative 7.
thank you @Jamal5337
Glad to help!
can you help w/ another problem
Sure
\[(\frac{ 1 }{ 2 }g+3) (\frac{ 1 }{ 2 }g-3)\]
This one is a bit more complex, so give me a second please. Lol
take your time! thanks for helping out
Do you know what the Distributive Property is?
is I do.
Okay, so the fact that this problem has a fraction in it makes it easier.
You can multiple fractions straight across. 1/2 times 1/2 is 1/4, including the x on both sides, this would be 1/4 x^2
Next, with the 3 on the other side, lets make that a fraction as well. the 3 would become 3/1
Since fractions are multiplied straight across, you would multiple 1/2 by 3/1, which would be 3/2
So so far, we got 1/4g^2, and -3/2 after distributing 1/2 to both terms on the right side.
yes im following
Alright,
I just remember a much easier way to do this, now that I think about it. Haha, let me tell you,
lol ok im listening
So, (1/2x+3)(1/2x-3) is equal to (1/2x)(1/2x)+(1/2x)(-3)+(3)(1/2x)+3(-3) Let me break this down into terms.
1/2x times 1/2x is equal to 1/4x squared
1/2x times -3 is equal to 1/2x times -3/1 which would be -3/2x
3 (1/2x) is equal to positve 3/2x
and 3 (-3) is equal to 9. Are you following?
yes im following
So far we have 1/4x squared -3/2x +3/2x minus 9
-3/2x and 3/2x cancels each other out, so you're left with 1/4x squared minus 9
That is the answer, was you confused with any parts?
So we started off with (1/2x+3)(1/2x-3) and by using the distributive property, we ended up with 1/4x squared-9
\[\frac{ 1 }{ 4 }g+9\] that was not confusing at all! I understand thank you for going step by step !
Yup! Need help with anything else?
I forgot how to do the distributive property for a while, that's why it took so long, sorry about that.
It's funny because I was working on it last year.
yes I have just one more: \[(\frac{ 1 }{ 3xy ^{2} })^{-4}\]
Okay, this one looks a bit easier.
Ever head of Please Excuse my Dear Aunt Sally? The order of Operations?
Or another acronym for it?
yes of course :)
Alright; first, lets add the exponent to the fraction.
We will add the power of negative 4 to every single thing into the fraction first.
Not literally add, but we will insert it.
following
Actually, it would be better to state this first;
Since the exponent is negative, instead of everything being multiplied as normal (2 times 2 equal 4), we would do it differently.
Let's take for an example, 2^-2; This wouldn't be two times negative two
Instead, we would be Undoing the multiplication in this equation, and the answer would be 1/2
ok still following
4^-2 is equal to 1/4; 4^-3 is equal to 1/16
normal powers, you'd multiply it constantly, but this time, since its negative, you'd divide continuously.
Actually, I made a mistake, 4 to the negative 2nd power is 1/16
This is proven because 4^2 is equal to 16, just add a 1 above the 16
4^3 is 64
4^-3 is 1/64 you understand?
You're basically finding the reciprocal.
It's important that you know this before we move onto the problem, where it gets more complicated.
im following! Im totally understanding
Good, before we move onto the problem, lets look at exponents in equations examples,
4x^2/4x^4 would be equal to 4x^6 let me explain why
In Division problems, exponents can be added and simplified to simplify the answer.
Actually excuse me, we would subtract.
Correction, 4x^2/4x^4 is equal to 1/x^2
Lets stretch the equation out to make it look more noticable,
4 times x^2 divided by 4 times x^4
Since the 4 in the numerator and denominator are exactly the same, we can divide these alone and that would be equal to 1
That's where you'd get the one from top from
We can divide x^2 by X^4 and get x^2
from this, an imaginary one would be at top along with the 1 already there.
So it would be (1 times 1) Divided by (x^2). We can simplify this more by multiplying 1 and 1, to get the lone 1. Which would mean the answer is 1/x^2
You understand so far?
or any questions before we move onto the problem that you need help with?
I hope your still on....yes I understand
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