Question

Is there anyone who can help me? logs.

Answer 1

Solve for n.\[\huge 9^{n+10}+3=81\]

Answer 2

ill help

Answer 3

Okay well I don't know what to do for this problem. Do I start by subtracting 3 on both sides?

Answer 4

yes if that is really the question you have to subtract 3 first

Answer 5

it would be a lot easier if it was
\[ 9^{n+10}+3=84\]

Answer 6

\[\huge 9^{n+10}=78\]

Answer 7

Now what do I do next? I know it's a logarithmic problem.

Answer 8

use the change of base formula
\[n+10=\frac{\ln(78)}{\ln(9)}\]

Answer 9

so
\[n=\frac{\ln(78)}{\ln(9)}-10\]

Answer 10

\[9^{n+10} + 3 = 81 \]
\[9^{n+10} = 78 \]
\[ln(9^{n+10})= ln 78 \]
\[(n + 10) \ln(9) = \ln(78) \]
\[n + 10 = \ln(78) / \ln(9)\]
\[n = [\ln(78) / \ln(9)] - 10\]
\[n ≈ -8.0172\]

Answer 11

that is what i get, yes

Answer 12

You type faster than I do hahaa. I was just making sure it was correct

Answer 13

Thank you!

Answer 14

yw