The estimated probability of a bowler getting strike during a particular frame is 41%. If several simulations of the bowler bowling 2 frames were performed, what percentage of the simulations would the bowler be most likely to get a strike in each of the two frames? A. 61% B. 38% C. 18% D. 81%
if we assume that the events are independent
we can multiply probabilities
So its 41% * 41% ?
let me think about it, one moment
yes i think thats right
ok, when i multiplied them i got 16.81%
I'm just unsure if i should be taking the percentage thats closest to 41 which would be 38 or not
18% could be the answer, it might be a typo
i could try this with a real simulation
oh ok cool, how do i do that?
yes i checked i got .41 * .41 = .1681 the closest answer looks like 18%
ok thanks!
also the questions says , what percentage would the bowler be most likely to bowl, so it is not asking for exact percentage, only whats closest
oh yea thanks(:
by the way, i was kidding. a real simulation is going bowling :)
hahaha awesome(:
you could simulate this with excel *
oh cool
but the nice thing about probability, we don't have to simulate . we can use our knowledge of how probability works . there are situations where we would have to use a simulation, since we simply dont know anything about it.
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