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Determine c so that f(x,y) satisfies the conditions of being a joint pmf for 2 discrete random variables X and Y \(f(x,y)=c(\dfrac{1}{4})^x(\dfrac{1}{3})^y\) x = 1, 2,....... y = 1, 2, ........ Please help
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is the answer 33/4 ?
6
pmf meaning?
probability mass function
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@ganeshie8 I see nothing on the wolfram , Is there something wrong?
so integral of the volume under the surface f(x,y) =1
@dan815 no, this is discrete, not continuous. We use sum, not integral
try entering below ``` \sum_{x=1}^{\infty}\sum_{y=1}^{x} ((1/4)^x*(1/3)^y) ```
well then trapezoid or cubes under the surface approximation then
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@ganeshie8 problem 4_1_1 d)
|dw:1417782516207:dw|
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