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Mathematics 15 Online
OpenStudy (anonymous):

Determine whether the given lengths can be sides of a right triangle...How do I do this?? Picture included.

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

test them using pythagorean theorem

ganeshie8 (ganeshie8):

they form a right triangle if a^2+b^2 = c^2

OpenStudy (anonymous):

Oh..I was thinking of doing that but I wasn't sure if it was the right thing to do

OpenStudy (anonymous):

Wait..I don't get it now...Would I put it like thIS? 14^2 + 24^2 = 26^2? And then add 14^2 and 24^2? And make it 772^2 = 26^2?

OpenStudy (anonymous):

Yeah, I don't get it..:c

OpenStudy (anonymous):

I don't think any of the lengths can be the lengths of a right triangle..

ganeshie8 (ganeshie8):

lets test wheher 14,24, 26 form a right triangle \[14^2 +24^2 \stackrel{?}{=} 26^2 \]

ganeshie8 (ganeshie8):

\[196 +576 \stackrel{?}{=} 676 \]

ganeshie8 (ganeshie8):

\[772 \not = 676 \] so those lengths cannot be sides of a right triangle

OpenStudy (anonymous):

So now I just need to test the others..alright.

ganeshie8 (ganeshie8):

yes

OpenStudy (anonymous):

Wait, how did you get 772?

ganeshie8 (ganeshie8):

add 196 and 576

OpenStudy (anonymous):

I thought soo..Okay, hang on.

OpenStudy (anonymous):

Why was there a slash in the equal sign? I just did 5^2 + 14^2 = 78^2...Then I added 30 + 72 and it became 102 = 6084..The 6084 is the 78^2..I think I messed up?

OpenStudy (anonymous):

Would the final two numbers (102 and 6084) need to be the same number in order for them to be able to be the lengths of a right triangle?

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

\(\ne \) is a symbol used for saying "not equal to"

OpenStudy (anonymous):

that's what I thought but I wasn't sure

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