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Mathematics 7 Online
OpenStudy (one098):

@waterineyes

OpenStudy (one098):

Find the solution of \[4\sqrt{x+2}=-16\]

OpenStudy (anonymous):

Start by squaring both the sides.. :)

OpenStudy (anonymous):

We both will confuse her.. Now she will think what to do.. :P

OpenStudy (one098):

oh gosh. guys... <_<

OpenStudy (one098):

I can try.

OpenStudy (anonymous):

Okay @Jhannybean I think you are better person than me to teach.. :P

OpenStudy (anonymous):

Or @One098 you want ONLY YOUR WATER to continue?? :P

OpenStudy (one098):

LOL sure

OpenStudy (anonymous):

Okay, we go according to beans said.. Divide by 4 first both the sides..

OpenStudy (one098):

So the 4 cancels on the left then I add it next to the -16?

OpenStudy (anonymous):

Add?

OpenStudy (anonymous):

\[\frac{4 \sqrt{x+2}}{4} = \frac{-16}{4}\]

OpenStudy (one098):

No not add as in something plus something... Yes, that^

OpenStudy (anonymous):

What you will get now?

OpenStudy (one098):

We have \[\sqrt{x+2}=\frac{ -16 }{ 4 }\]

OpenStudy (anonymous):

Can you simplify right hand side?

OpenStudy (one098):

\[\sqrt{x+2}=-4\]

OpenStudy (anonymous):

Now square both the sides..

OpenStudy (one098):

\[(x+2)(x+2)=16\]

OpenStudy (anonymous):

you sure?

OpenStudy (one098):

-16

OpenStudy (anonymous):

Suppose you have a number for example : \(4\).. When we square it, we do like : \(4 \times 4\), okay?

OpenStudy (jhannybean):

\[(\sqrt{x})^2 \ne (x)(x)\]

OpenStudy (one098):

Yes, @waterineyes

OpenStudy (anonymous):

So when you square that : \[\sqrt{x+2} = \sqrt{x+2} \times \sqrt{x+2}\]

OpenStudy (anonymous):

Right??

OpenStudy (one098):

yes

OpenStudy (anonymous):

And : \[\sqrt{a} \times \sqrt{a} = a\]

OpenStudy (anonymous):

So, on left hand side on square, what you get?

OpenStudy (one098):

yes

OpenStudy (anonymous):

you got yes?

OpenStudy (anonymous):

From squaring mathematical terms, you got English words?

OpenStudy (one098):

No >_< This thing is messed up.

OpenStudy (anonymous):

Wait.. Here are we now: \(\sqrt{x+2} = -4\), Okay?

OpenStudy (one098):

Yes.

OpenStudy (anonymous):

Now I said to square both the sides: \[(\sqrt{x+2})^2 = (-4)^2 \\ \sqrt{x+2} \times \sqrt{x+2} = (-4) \times (-4)\] All good till now?

OpenStudy (one098):

Yes .

OpenStudy (anonymous):

Now I also said: \(\sqrt{a} \times \sqrt{a} = a\)

OpenStudy (one098):

Ok.

OpenStudy (anonymous):

When you square, square root(opposite of square), gets cancel thereby giving you original number..

OpenStudy (anonymous):

\[\sqrt{4} \times \sqrt{4} = 4\]

OpenStudy (one098):

Ok.

OpenStudy (anonymous):

Likewise, on left hand side, what you will get?

OpenStudy (anonymous):

\(\sqrt{x+2} \times \sqrt{x+2} = ??\)

OpenStudy (one098):

\[\sqrt{x+2}\]

OpenStudy (anonymous):

The square root \(\sqrt{...}\), will not get cancelled?

OpenStudy (one098):

Oh yes so its x+2

OpenStudy (anonymous):

That black is not looking good to me, let us make that colorful.. :P

OpenStudy (anonymous):

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