Mathematics
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OpenStudy (one098):
@waterineyes
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OpenStudy (one098):
Find the solution of \[4\sqrt{x+2}=-16\]
OpenStudy (anonymous):
Start by squaring both the sides.. :)
OpenStudy (anonymous):
We both will confuse her.. Now she will think what to do.. :P
OpenStudy (one098):
oh gosh. guys... <_<
OpenStudy (one098):
I can try.
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OpenStudy (anonymous):
Okay @Jhannybean I think you are better person than me to teach.. :P
OpenStudy (anonymous):
Or @One098 you want ONLY YOUR WATER to continue?? :P
OpenStudy (one098):
LOL sure
OpenStudy (anonymous):
Okay, we go according to beans said..
Divide by 4 first both the sides..
OpenStudy (one098):
So the 4 cancels on the left then I add it next to the -16?
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OpenStudy (anonymous):
Add?
OpenStudy (anonymous):
\[\frac{4 \sqrt{x+2}}{4} = \frac{-16}{4}\]
OpenStudy (one098):
No not add as in something plus something... Yes, that^
OpenStudy (anonymous):
What you will get now?
OpenStudy (one098):
We have \[\sqrt{x+2}=\frac{ -16 }{ 4 }\]
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OpenStudy (anonymous):
Can you simplify right hand side?
OpenStudy (one098):
\[\sqrt{x+2}=-4\]
OpenStudy (anonymous):
Now square both the sides..
OpenStudy (one098):
\[(x+2)(x+2)=16\]
OpenStudy (anonymous):
you sure?
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OpenStudy (one098):
-16
OpenStudy (anonymous):
Suppose you have a number for example : \(4\)..
When we square it, we do like : \(4 \times 4\), okay?
OpenStudy (jhannybean):
\[(\sqrt{x})^2 \ne (x)(x)\]
OpenStudy (one098):
Yes, @waterineyes
OpenStudy (anonymous):
So when you square that :
\[\sqrt{x+2} = \sqrt{x+2} \times \sqrt{x+2}\]
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OpenStudy (anonymous):
Right??
OpenStudy (one098):
yes
OpenStudy (anonymous):
And :
\[\sqrt{a} \times \sqrt{a} = a\]
OpenStudy (anonymous):
So, on left hand side on square, what you get?
OpenStudy (one098):
yes
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OpenStudy (anonymous):
you got yes?
OpenStudy (anonymous):
From squaring mathematical terms, you got English words?
OpenStudy (one098):
No >_< This thing is messed up.
OpenStudy (anonymous):
Wait..
Here are we now:
\(\sqrt{x+2} = -4\), Okay?
OpenStudy (one098):
Yes.
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OpenStudy (anonymous):
Now I said to square both the sides:
\[(\sqrt{x+2})^2 = (-4)^2 \\ \sqrt{x+2} \times \sqrt{x+2} = (-4) \times (-4)\]
All good till now?
OpenStudy (one098):
Yes .
OpenStudy (anonymous):
Now I also said: \(\sqrt{a} \times \sqrt{a} = a\)
OpenStudy (one098):
Ok.
OpenStudy (anonymous):
When you square, square root(opposite of square), gets cancel thereby giving you original number..
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OpenStudy (anonymous):
\[\sqrt{4} \times \sqrt{4} = 4\]
OpenStudy (one098):
Ok.
OpenStudy (anonymous):
Likewise, on left hand side, what you will get?
OpenStudy (anonymous):
\(\sqrt{x+2} \times \sqrt{x+2} = ??\)
OpenStudy (one098):
\[\sqrt{x+2}\]
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OpenStudy (anonymous):
The square root \(\sqrt{...}\), will not get cancelled?
OpenStudy (one098):
Oh yes so its x+2
OpenStudy (anonymous):
That black is not looking good to me, let us make that colorful.. :P
OpenStudy (anonymous):
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