Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels 14 miles per hour faster than the westbound train. If the two trains are 1000 miles apart after 5 hours, what is the rate of the eastbound train?
Not really. I'm not good at the distance, rate and time equations :/
Need answer or method?
method and answer
|dw:1417794435278:dw|
Let denote: \(V_W \) is the velocity of the train goes to Westbound. \(V_E\) is the velocity of the train goes to Eastbound. then \(V_E= V_W+14\) got this part?
Kinda
Let \(X_W \) is the distance the westbound train goes, then after 5 hours, \(X_W= V_W*5\) \(X_E\) is the distance the eastbound train goes, then after 5hours, \(X_E= V_E*5 = (V_W+14)*5\)
And we know that after 5hours, the distance between them is 1000 miles, hence \(5V_W + (V_W+14)5=1000\) solve for \(V_W\) then plug back to get \(V_E\)
I got V=93
yes, then +14 to get \(V_E\)
Thank you!
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