Question

x^2+1/8

Answer 1

OK, and what do you need to do?

Answer 2

i have to factor it but theres no like terms ;-;

Answer 3

I don't think if you can do more in it..

Answer 4

Well... \(\dfrac{8}{8}x^2+\dfrac{1}{8} ~~~=~~~ \dfrac{1}{8}(8x^2+1)\)

Answer 5

I don't see how else it can be factored.

Answer 6

\[(x- i \frac{1}{2 \sqrt{2}})(x+ i \frac{1}{2 \sqrt{2}})\] :P

Answer 7

it has to have 1/2 in it
cause its a little thing that i ahve to fill in the blank

Answer 8

You sure it's \(x^2+\dfrac{1}{8}\) and not \(x^3+\dfrac{1}{8}\)?

Answer 9

@geerky42

Answer 10

I knew it. Just remember that \(a^3+b^3 = (a+b)(a^2-ab+b^2)\)

So you have \(x^3 + \left(\dfrac{1}{2}\right)^3 = ~\cdots~?\)