Question

Another simple circuits problem, am not really good at these yet.

Answer 1

I'm supposed to find the equivalent resistance between points A and B in the following circuit, one moment.

Answer 2

(One second, just trying to startup a screenshot program so I can put up the original prompt.)

Answer 3

im familiar with logical circuits/gates. this is a little beyond me though im afraid.

Answer 4

Where are points A and B in that picture link?

Answer 5

I made a mistake, I put up the wrong question entirely; this one is just asking for the ammeter reading by itself, which I also am interested in finding; could you also help me on some other basic circuits problems?

Answer 6

(The other question I had, which is probably easier, is the original prompt with the following diagram): http://i.imgur.com/n3GmzMs.png

Answer 7

No Problemoo!
in each loop, you have to try unite all the resistors in a given straight line to sum them up, so that when you look to the circuit, it appears that from the point where the loops begins, it branches to 2 or more straight branches.
Taking this imaginary scheme, to the most left, we have a combination of R and 2 R and since these are in series become 3 R. The same occurs in the most RHS.
Before I continue... What is the answer ?

Answer 8

The answer is 7R/5, which is not what I got by doing what you did and summing them in parallel. One second.

Answer 9

\[\frac{1}{3R}+\frac{1}{3R}+\frac{1}{R}=\frac{1}{R_{tot}}\]

Answer 10

@Hoslos

Answer 11

@radar

Answer 12

the first thing you should be doing is redrawing and simplifying the circuit to see clearly what is in series and what is in parallel. This is a fundamental part of circuit analysis

Answer 13

I'm not sure how I should be "redrawing" it. I've never been taught to do that, only to relabel it, and it looks elementary enough to not need to do that. Care to tell me how to do that?

Answer 14

@surry99

Answer 15

Let me send a link that might help you...
https://www.youtube.com/watch?v=In3NF8f-mzg

Answer 16

My circuit looks much simpler than this; it literally looks like three parallel lines, I have no idea how you expect me to simplify it further.

Answer 17

How does this get any simpler than this?

Answer 18

I don't think any of the resistors are connected in series or parallel.

Answer 19

I've been actively trying to get this question answered for a long time. I'm just trying to get it done. Meaningful help is appreciated.

Answer 20

"I don't think any of the resistors are connected in series or parallel."

That doesn't mean anything to me because it isn't physically possible to have a circuit where they are connected in neither; how would you suggest finding the total resistance if they are all in neither series nor parallel?

Answer 21

They are not connected in series or parallel draw the diagram that shows this if you can.

Answer 22

Again, you both keep telling me to draw something; I have no idea what you're asking me to draw, I can't draw what I have no idea what you are talking about.

I posted the original prompt with the circuit diagram.

I wrote another one in the editor.

I'm not sure what else you want me to draw, and telling me to draw something that I don't know to do, like the last guy did, isn't helping; thank you for trying, this just feels seriously futile because the way people are trying to help isn't very helpful at the moment.

Answer 23

I don't know how to do what both of you are asking me to do, thus, I can't do it yet.

Answer 24

In my drawing R1 is in series with the parallel combo R2and R3 can you redraw you circuit so that the resistors are connect in this way. I think not.



This what is know as a bridge circuit. I can be solved by finding the ratio of the voltage divided by the current it is delivering using Kirchhoff's Laws