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Mathematics 7 Online
OpenStudy (anonymous):

The following table shows the probability distribution for a discrete random variable. X 22 24 25 30 33 37 P(X) 0.16 0.09 0.18 0.12 0.24 0.21 What is the mean of this discrete random variable? That is, what is E(X), the expected value of X? A. 30.27 B. 27.5 C. 29.47 D. 28.5

OpenStudy (kropot72):

\[\large E(X)=\sum_{}^{}xp(x)\] The first two terms are (22 * 0.16) and (24 * 0.09)

OpenStudy (kropot72):

The expected value is the sum of six terms: \[\large E(X)=(22\times0.16)+(24\times0.09)+...................+(37\times0.21)\] Can you put in the missing three terms, and then add the six terms?

OpenStudy (anonymous):

29.47?

OpenStudy (anonymous):

then what do i do?

OpenStudy (anonymous):

@kropot72

OpenStudy (kropot72):

The expected value is the mean. You have finished. Obviously the correct choice is C.

OpenStudy (anonymous):

haha sorry

OpenStudy (kropot72):

np

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