Mathematics
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OpenStudy (anonymous):
How can I find X here? |Solving for X|
2x + 1 = x2 + 4x + 18
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OpenStudy (anonymous):
@tHe_FiZiCx99
OpenStudy (anonymous):
@Zarkon
OpenStudy (anonymous):
Ok, looks like I can use the quadratic formula. Can someone help me apply it?
OpenStudy (anonymous):
@jigglypuff314
jigglypuff314 (jigglypuff314):
first get all the stuff to one side
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OpenStudy (anonymous):
Do you mean combine like terms?
OpenStudy (anonymous):
And get X to one side?
jigglypuff314 (jigglypuff314):
subtract 2x and 1 from both sides
then quadratic
OpenStudy (anonymous):
Ok, thanks. Check my answer when I'm done?
jigglypuff314 (jigglypuff314):
sure :)
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OpenStudy (anonymous):
Ok, I have the problem set up.
OpenStudy (anonymous):
\[x = \frac{ -2x plusorminus \sqrt{4x^2 - 4(x^2 * 17)} }{ 2x^2 }\]
OpenStudy (anonymous):
plusorminus = ±
OpenStudy (anonymous):
Ugh.
OpenStudy (anonymous):
Did I set up the equation correctly?
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jigglypuff314 (jigglypuff314):
\[\pm \]
OpenStudy (anonymous):
Yes, I couldn't find it lol
jigglypuff314 (jigglypuff314):
ummm the quadratic equation is just for the coefficients
the whole point was to take the x's out of there to solve for it :)
jigglypuff314 (jigglypuff314):
\[\frac{ -2\pm \sqrt{(2)^2-4(1)(17)} }{ 2(1) }\]
jigglypuff314 (jigglypuff314):
oh wait O_O
there are no real answers!!!
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jigglypuff314 (jigglypuff314):
@superdude123 ... are you learning imaginary?
OpenStudy (anonymous):
Sorry!
OpenStudy (anonymous):
Why are there no real answers?
OpenStudy (anonymous):
I graphed it an they don't intersect, which means there is no answer.
jigglypuff314 (jigglypuff314):
square root ( 4 - (4*17) ) = squareroot(negative) = imaginary number
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OpenStudy (anonymous):
So should I say that the answer is extraneous?
OpenStudy (anonymous):
Or the equation, rather.
jigglypuff314 (jigglypuff314):
um more like there are no real solutions
OpenStudy (anonymous):
Prime?
jigglypuff314 (jigglypuff314):
umm I just think it's no real solutions
unless you have options?
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OpenStudy (anonymous):
Nope, that's fine. Thanks for your help. :)