How much work is required to stretch a spring 0.139m if its force constant is 9.10N/m ? Answer in units of J. Thanks!!
@mathstudent55 help please!!
What is the equation for the work done by a linear spring?
not sure, i am totally lost haha
F=-kX? @surry99
http://www.batesville.k12.in.us/physics/phynet/mechanics/energy/spring_work_2.htm
- 0.0879 J Step by step answer http://www.mathskey.com/question2answer/24047/much-work-required-stretch-spring-139m-its-force-constant-10n
please note that work W done by stretch your spring will be storage by that spring as potential energy, so: \[W=\frac{ 1 }{ 2 }k \Delta ^{2}\] where k is spring constant and Delta is the displacement. So inserting your numerical data, you will get: \[W=\frac{ 1 }{ 2 }*9.1*(0.139)^{2}=0.0879Joules\]
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