Question

Calculus Question, would appreciate some help. Screenshot in the comments.

Answer 1

x^3 = 25x
x^2 = 25
x = 5

y = 5^3
y = 125

Answer: x = 5, y = 125

Answer 2

I don't believe that is the answer I'm looking for?

Answer 3

Yes i am seeing the same i did something totally different... hmm

Answer 4

that indeed how i would start though... you need to find intersection points first

Answer 5

he was trying to find the intersections
x^3=25x
x^3-25x=0
x(x^2-25)=0
x(x-5)(x+5)=0
intersections @ x=0 x=5, x=-5
one of these we care nothing for

Answer 6

Ok so we found intersections...what from there?

Answer 7

Plotting the graphs it can be seen that at x = 5, the two functions cross and do not enclose any area beyond x = 5, so I will use the limits from x = 0 to x = 5
= Lim 0 to 5 ∫ π [(25x)^2 - (x^3)^2]dx
= Lim 0 to 5 π [(625x^3)/3 - (x^7)/7]
= \[ \pi\] [625 * 125/3 - (5^7)/7 - 0]
= \[ \pi\] * 14880.95 cubic units
= 46749.88 cubic units

Answer 8

dang it i was busy typing and not looking to see if i made mistakes

Answer 9

hahaha it's ok! That was the right answer!

Answer 10

Oh ok i was gonna rewrite it lol

Answer 11

Ans:14880.95pi
Step by step answer http://www.mathskey.com/question2answer/24043/find-the-volume