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Mathematics 13 Online
OpenStudy (anonymous):

Some workers are to stay in a dormitory with 50 rooms. How many workers must there be to guarantee that at least one of the rooms will have at least 5 workers?

OpenStudy (anonymous):

how do i apply pigeonhole principle in this case?

OpenStudy (anonymous):

wait this is a math question

OpenStudy (fibonaccichick666):

pidgeonhole principle?

OpenStudy (anonymous):

yes

OpenStudy (fibonaccichick666):

no clue what that is, but I would assume this method, how many workers would you need to have exactly 4 per room?

OpenStudy (fibonaccichick666):

but that is if there is an even displacement,

OpenStudy (fibonaccichick666):

you see there is also a smart alec response to this

OpenStudy (anonymous):

LOL no replacement

OpenStudy (fibonaccichick666):

what?

OpenStudy (anonymous):

We are supposed to find the number of workers so that at least one of the rooms will have 5 workers in it.

OpenStudy (fibonaccichick666):

ok, so let's go with smart alec response

OpenStudy (fibonaccichick666):

what if you have 5 bffs?

OpenStudy (anonymous):

this isnt multiple choice

OpenStudy (anonymous):

exactly

OpenStudy (fibonaccichick666):

...why are you asking that? this is a logic question. Multiple choice is the ruin of math... i swear

OpenStudy (fibonaccichick666):

but so yea, i would have two answers here, my smart alec answer and my "I'm reading the question and I know what you want, but you should have stated it better" answer

OpenStudy (fibonaccichick666):

so, let's talk about the should've stated it better answer

OpenStudy (anonymous):

please do so :D

OpenStudy (fibonaccichick666):

so I pose, if you were to evenly distribute the peopple into the rooms, how many workers would you need for 1 worker in each?

OpenStudy (anonymous):

i dont know

OpenStudy (fibonaccichick666):

oh come on... you have 50 rooms

OpenStudy (fibonaccichick666):

you put 1 person in each, how many people?

OpenStudy (anonymous):

50 rooms in total if 1 person in one room

OpenStudy (fibonaccichick666):

ok how about 2?

OpenStudy (anonymous):

100!

OpenStudy (fibonaccichick666):

ok how about 3?

OpenStudy (anonymous):

150

OpenStudy (fibonaccichick666):

4?

OpenStudy (anonymous):

200!

OpenStudy (fibonaccichick666):

ok so now, you have evenly distributed 4 people into each room. What is the minimum number you would need to have 1 room with 5 people?

OpenStudy (anonymous):

+1 LOL

OpenStudy (anonymous):

DAMN IT MAN

OpenStudy (fibonaccichick666):

what +1?

OpenStudy (fibonaccichick666):

please be specific so I know you got it right

OpenStudy (anonymous):

According to the pigeonholes principle, if the number of workers is greater than the amount of rooms available. Then at least 5 workers will share the room.

OpenStudy (anonymous):

same*

OpenStudy (fibonaccichick666):

ok the non smart alec solution

OpenStudy (anonymous):

BUT IT MAKES SENSE DUDE

OpenStudy (fibonaccichick666):

your explanation is wrong though dude

OpenStudy (fibonaccichick666):

by the pigeonhole principle, your answer is wrong. You need the second solution we got

OpenStudy (anonymous):

whats the second solution?

OpenStudy (fibonaccichick666):

... the +1 solution I was asking you for

OpenStudy (fibonaccichick666):

ie, what number +1

OpenStudy (anonymous):

pigeon + 1

OpenStudy (anonymous):

number of workers needed

OpenStudy (fibonaccichick666):

... please tell me you are messing with me and we didn't just spend 15 minutes solving this and you still don't know the answer

OpenStudy (anonymous):

THE ANS IS 201 DUDE

OpenStudy (fibonaccichick666):

thankyou

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