Some workers are to stay in a dormitory with 50 rooms.
How many workers must there be to guarantee that at least one of the rooms will have at least 5 workers?
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OpenStudy (anonymous):
how do i apply pigeonhole principle in this case?
OpenStudy (anonymous):
wait this is a math question
OpenStudy (fibonaccichick666):
pidgeonhole principle?
OpenStudy (anonymous):
yes
OpenStudy (fibonaccichick666):
no clue what that is, but I would assume this method, how many workers would you need to have exactly 4 per room?
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you see there is also a smart alec response to this
OpenStudy (anonymous):
LOL no replacement
OpenStudy (fibonaccichick666):
what?
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OpenStudy (anonymous):
We are supposed to find the number of workers so that at least one of the rooms will have 5 workers in it.
OpenStudy (fibonaccichick666):
ok, so let's go with smart alec response
OpenStudy (fibonaccichick666):
what if you have 5 bffs?
OpenStudy (anonymous):
this isnt multiple choice
OpenStudy (anonymous):
exactly
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OpenStudy (fibonaccichick666):
...why are you asking that? this is a logic question. Multiple choice is the ruin of math... i swear
OpenStudy (fibonaccichick666):
but so yea, i would have two answers here, my smart alec answer and my "I'm reading the question and I know what you want, but you should have stated it better" answer
OpenStudy (fibonaccichick666):
so, let's talk about the should've stated it better answer
OpenStudy (anonymous):
please do so :D
OpenStudy (fibonaccichick666):
so I pose, if you were to evenly distribute the peopple into the rooms, how many workers would you need for 1 worker in each?
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OpenStudy (anonymous):
i dont know
OpenStudy (fibonaccichick666):
oh come on... you have 50 rooms
OpenStudy (fibonaccichick666):
you put 1 person in each, how many people?
OpenStudy (anonymous):
50 rooms in total if 1 person in one room
OpenStudy (fibonaccichick666):
ok how about 2?
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OpenStudy (anonymous):
100!
OpenStudy (fibonaccichick666):
ok how about 3?
OpenStudy (anonymous):
150
OpenStudy (fibonaccichick666):
4?
OpenStudy (anonymous):
200!
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OpenStudy (fibonaccichick666):
ok so now, you have evenly distributed 4 people into each room. What is the minimum number you would need to have 1 room with 5 people?
OpenStudy (anonymous):
+1 LOL
OpenStudy (anonymous):
DAMN IT MAN
OpenStudy (fibonaccichick666):
what +1?
OpenStudy (fibonaccichick666):
please be specific so I know you got it right
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OpenStudy (anonymous):
According to the pigeonholes principle, if the number of workers is greater than the amount of rooms available. Then at least 5 workers will share the room.
OpenStudy (anonymous):
same*
OpenStudy (fibonaccichick666):
ok the non smart alec solution
OpenStudy (anonymous):
BUT IT MAKES SENSE DUDE
OpenStudy (fibonaccichick666):
your explanation is wrong though dude
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OpenStudy (fibonaccichick666):
by the pigeonhole principle, your answer is wrong. You need the second solution we got
OpenStudy (anonymous):
whats the second solution?
OpenStudy (fibonaccichick666):
... the +1 solution I was asking you for
OpenStudy (fibonaccichick666):
ie, what number +1
OpenStudy (anonymous):
pigeon + 1
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OpenStudy (anonymous):
number of workers needed
OpenStudy (fibonaccichick666):
... please tell me you are messing with me and we didn't just spend 15 minutes solving this and you still don't know the answer