Question

A coil consists of three turns of wire. Each turn encloses an area of 5.0 x?10^-4 m2. The
plane of the coil is positioned at 60° to the direction of a magnetic field of 0·25 T.
What is the value of the magnetic flux through the coil?

Answer 1

I ask you, what is the value of the component of magnetic field along the coil direction?

Answer 2

@Leo7 please try

Answer 3

if B_0 is the magnetic field, which is the value of the component of B_0 along the coil axis

Answer 4

B=0.25 T

Answer 5

B = 0.25cos(60)

Answer 6

please note that you coil have not the direction of magnetic field, so the component must be less than o.25 T,
it is equals to:
\[0.25*\cos(60°)=...\]
please try to calculate

Answer 7

Does the 3 turns have any effect on the equation?
The equation i am using is B(flux) = BAcos(x)

Answer 8

yes! because your magnetic field is acting on each turn:
so flux=
\[N*0.25*\cos(60°)*(area of each turn)\]

Answer 9

I'm sorry but your equations kept on coming out as [Math Processing Error]

Answer 10

flux across each turn is:
0.25*cos(60°)*5*10^(-4)
are you agree?

Answer 11

yup

Answer 12

ok, now you have to multiply that number by N, which is total turns, namely N=3, please.
are you agree, please?

Answer 13

yup

Answer 14

ok, we got your answer!

Answer 15

i will get 1.875 x 10^-4

Answer 16

that's right!

Answer 17

ans : 3.2 x 10^-4Wb

Answer 18

I see, let me think....

Answer 19

how do you got your answer?

Answer 20

from my lecturer's tutorial answer

Answer 21

but don't have the solutions

Answer 22

is the tutorial equals to our exercise?

Answer 23

yup

Answer 24

may be a printing error?

Answer 25

oh I see. Thanks for your help.

Answer 26

thanks!

Answer 27

@Leo7 I got your explamnation

Answer 28

try this, in other word B is:
0.25*cos(30°)