OK, I need someone who can show me step by step how to solve this equation (put it to this form ax2+bx+c) :

Kc = ((2x)^2 * (2x)^2) /((0.53-2x)^2 * (0.515-x)) = 9.14 * 10^-6

Thank you very much! cant get the right answere!

Question

OK, I need someone who can show me step by step how to solve this equation (put it to this form ax2+bx+c) : 

Kc = ((2x)^2 * (2x)^2) /((0.53-2x)^2 * (0.515-x)) = 9.14 * 10^-6

Thank you very much! cant get the right answere!

aaronq · Answer

it's just math

$\dfrac{(2x)^2 * (2x)^2}{ (0.53-2x)^2 * (0.515-x)} = 9.14 * 10^{-6}$

$\dfrac{4x^2 * 4x^2}{ (0.53-2x)*(0.53-2x) * (0.515-x)} = 9.14 * 10^{-6}$

$\dfrac{16x^4}{ (0.2809-2.12x +4x^2)* (0.515-x)} = 9.14 * 10^{-6}$

etc

aaronq · Answer

keep expanding the bottom first

anonymous · Answer

Thank you!
But now I got this:    16x^4/(0.145 - 1.373x + 4.18x^2 - 4x^3)

what do I do next?

aaronq · Answer

are you sure you can't omit some of the values to simplify it?

you're ending up with a quartic function thats pretty much impossible to solve by hand lol