solve abs(2x+6)>= abs(9x-8), answer in interval form
\(\large\color{blue}{ \left| 2x+6 \right|= \left| 9x-8 \right| }\) should be converted to, \(\large\color{blue}{ 2x+6 =\pm( 9x-8 ) }\).
where you would have 2 solutions for x.
are you sure about that?
\[|2x+6|=\begin{cases} -2x+6\\ 2x+6 \end{cases}\]
I am fairly sure. Reason. when you say that a^2=b^2 (and this statement you can see when you complete the square) you don't say that +-a=+-b No... you just say a=+-b
here, it is sort of the same.
ahh that gives me another idea
\[\sqrt{ 2x+6 } ^{ 2 } \ge\sqrt{ 9x-8 } ^{ 2 } \]
yeah, my sign was off, it should be \(\large\color{blue}{ \ge}\) but you got the idea of my first statement though.
nevermind im not sure how to get plus minus from this
well, you know that if \(\large\color{blue}{ \left| x \right|=a}\), then \(\large\color{blue}{ x=\pm a}\)
mm so i solved your \(\large\color{blue}{ 2x+6 =\pm( 9x-8 ) }\)
but it doesn't quite fit with the graph
neither does the answers at the critical points match
wait wait
nevermind it worked XD did bad math
im curious though about your example a^2=b^2 becoming \(a= \pm b\)
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