Please help. giving medal What is the approximate mean absolute deviation of the data below? 30.9, 22.3, 30.4, 33.4, 21.2, 22.1, 30.8, 32.1, 23.4, 246.6
plz help
added up its 493.1
then you divide by 10, so move the decimal point over.
49.31?
Yes. There ya go. The mean is always the sum of the numbers divided by the amount of numbers, if I am not mistaken.
wait that's not one of the answer choices...
4.578 1.822 6.2 16.4 i'm so confused
have a look at this article http://mathbits.com/MathBits/TISection/Statistics1/MAD.html
Wait, I;m sorry, I have calculated it wrong, I was finding standard mean. My bad.
i don't really understand it @jim_thompson5910
which part doesn't make sense?
the subtraction???
you subtract each value from the mean and take the absolute value of that difference (to make sure it's positive)
It looks like you already found the mean to be 49.31 so \[\Large \mu = 49.31\] or \[\Large \overline{x} = 49.31\]
okay i think i got i can do it
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