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Mathematics 9 Online
OpenStudy (anonymous):

Please help. giving medal What is the approximate mean absolute deviation of the data below? 30.9, 22.3, 30.4, 33.4, 21.2, 22.1, 30.8, 32.1, 23.4, 246.6

OpenStudy (anonymous):

plz help

OpenStudy (anonymous):

added up its 493.1

OpenStudy (anonymous):

then you divide by 10, so move the decimal point over.

OpenStudy (anonymous):

49.31?

OpenStudy (anonymous):

Yes. There ya go. The mean is always the sum of the numbers divided by the amount of numbers, if I am not mistaken.

OpenStudy (anonymous):

wait that's not one of the answer choices...

OpenStudy (anonymous):

4.578 1.822 6.2 16.4 i'm so confused

jimthompson5910 (jim_thompson5910):

have a look at this article http://mathbits.com/MathBits/TISection/Statistics1/MAD.html

OpenStudy (anonymous):

Wait, I;m sorry, I have calculated it wrong, I was finding standard mean. My bad.

OpenStudy (anonymous):

i don't really understand it @jim_thompson5910

jimthompson5910 (jim_thompson5910):

which part doesn't make sense?

OpenStudy (anonymous):

the subtraction???

jimthompson5910 (jim_thompson5910):

you subtract each value from the mean and take the absolute value of that difference (to make sure it's positive)

jimthompson5910 (jim_thompson5910):

It looks like you already found the mean to be 49.31 so \[\Large \mu = 49.31\] or \[\Large \overline{x} = 49.31\]

OpenStudy (anonymous):

okay i think i got i can do it

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