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(True or false.) Let V be an n-dimensional vector space, and let S be a k-dimensional subspace of V, where k < n. If {⃗v1,...,⃗vk} is a basis for S and {⃗vk+1,...,⃗vn} is a set of n − k linearly independent vectors not in S, then {v1,...,⃗vk,⃗vk+1,...,⃗vn} is a basis for V.
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It is indeed false. Example: \(V = \mathbb{R}^3\) \(v_1 = (1, 0, 0)\) \(S = \text{span}\ \{v_1\}\) \(v_2 = (1, 1, 1)\) \(v_3 = (0, 1, 1)\) Notice that \(\{v_2, v_3\}\) is linearly independent and \(v_2, v_3 \not\in S\). Yet \(\{v_1, v_2, v_3\}\) is not linearly independent since \(v_1 = v_2 - v_3\). Therefore \(\{v_1, v_2, v_3\}\) is not a basis for \(\mathbb{R}^3\).
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