A group of four components is known to contain two defectives. An inspector tests the components one at a time until the two defectives are located. Once she locates the two defectives, she stops testing, but the second defective is tested to ensure accuracy. Let Y denote the number of the test on which the second defective is found. Find the probability distribution for Y .pdf

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compassionate · Answer

Hey, Welcome to OpenStudy! I'm going to get someone that can help you, as I don't do good with this type of stuff! :) 

@Data_LG2 , @paki . @goformit100

paki · Answer

any idea of probability....? @Khalid1981

anonymous · Answer

Evaluate $$\int\limits_{0}^{\infty}( sinax+asinx)dx/x^3$$  , where a>0 is a constant ,using residues. Please I want help as soon as possible .I appreciate

anonymous · Answer

This is for Complex analysis please please help me

paki · Answer

i will help... but you have posted 2 questions....? and it is against the code of conduct of open study, when we put one than more question in the same thread....

anonymous · Answer

I want details for my equations

kropot72 · Answer

Did you want me to try to guide you through the first question (probability distribution)?

anonymous · Answer

I want it by complex analysis way please if possible

kropot72 · Answer

(1) The probability of a second defective component being found on the first test is obviously 0.
(2) The probability of a defective component being found on the first test is 2/4. If a defective component is found on the first test, the probability of a second defective component being found on the second test is 1/3 and the probability of a second defective component being found on the third test is 1/2.

@Khalid1981 Do you follow the above reasoning?