Question

The components of vector A are Ax= 2 and Ay= -3 while that of another vector B are Bx=-3 and by= 2.22. What is the smallest angle between vectors A and B?

Answer 1

@incredebility

Answer 2

@hoslos

Answer 3

cos theta=(A.B)/(|A|*|B|)

Answer 4

the nr is a dot product

Answer 5

what do u mean by A.B? is it A*B?? @incredebility

Answer 6

A.B means dot product multiply the corresponding x component and y components

Answer 7

(2*-3)+(-3*2.22)

Answer 8

the denominator is modulus... u know hw to take modulus?

Answer 9

HAHA what is modulus?

Answer 10

|A|=sqrt(2^2 + -3^2)

Answer 11

problem is that the theta is not given

Answer 12

tht theta is cos^-1 of the RHS

Answer 13

can u give me the whole solution? i cant understand it. maybe you have your own formulas and so am i..

Answer 14

@incredebility

Answer 15

theta=cos^-1( (2*-3)+(-3*2.22) / sqrt(2^2 + -3^2) * sqrt(-3^2 + 2.22^2) )

Answer 16

@incredebility i didnt get the right answer :(