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Find the linearization L(x) of f(x) at x=a. F(x)=x+(1/x) a=1
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I have done it but I do no have the right answer.
your function is, \(\Large\color{black}{F(x)=\frac{x+1}{x} }\) , and ` a = 1 `. Correct?
\(\large\color{black}{\frac{d}{dx} (\frac{x+1}{x})=\frac{(x+1)'~x~-~x'(x+1)}{x^2} }\)
you just need the derivative of 1) ` x + 1 ` : 2) ` x ` :
so 1+0=1 and 1
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yes, the derivative of both of the functions, of x+1, and of x, is 1.
So, now fund the derivative of the (x+1)/x based on the aforementioned quotient rule.
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