Which equation is of a circle that has a center at (3, -2) and a radius of 9?

Question

anonymous · Answer

(x + 3)2 + (y - 2)2 = 9

	
(x + 3)2 + (y - 2)2 = 81

	
(x - 3)2 + (y + 2)2 = 9

	
(x - 3)2 + (y + 2)2 = 81

anonymous · Answer

@SolomonZelman

solomonzelman · Answer

$\large\color{black}{   (x-h)^2+(y-k)^2 +r^2                 }$
where $\large\color{black}{   (h,k)          }$ is the center, and $\large\color{black}{ r         }$ is the radius.

solomonzelman · Answer

I meant,   $\large\color{black}{   (x-h)^2+(y-k)^2 =r^2                 }$
and so,

$\large\color{black}{   (x-(3)~)^2+(y-(-2)~)^2 =9^2                 }$

solomonzelman · Answer

can you finish it?

anonymous · Answer

How do i finish it ?

solomonzelman · Answer

can you finish it?

anonymous · Answer

No :(

anonymous · Answer

But i thinking it is the last answer choice ?

solomonzelman · Answer

$\large\color{black}{  a-(-b)=a+b             }$

solomonzelman · Answer

yes, it is
$\large\color{black}{   (x-3)~)^2+(y+2)^2 =81               }$

anonymous · Answer

Thank you :) i am going to graduate

solomonzelman · Answer

Lol, :) yw

anonymous · Answer

I will let you know if i have other questions sir :) ;)