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Physics 6 Online
OpenStudy (zephyr141):

satellites and orbits

OpenStudy (zephyr141):

if a new satellite is placed in a circular orbit at a distance of\[\left| r_2 \right|=4\left| r_1 \right|\]around the same planet what is the ratio\[\frac{v_1}{v_2}\]between the speed of the first satellite and the speed of the new satellite?

OpenStudy (zephyr141):

the choices are... A. (2)^(1/2) B. 1/[(2)^(1/2)] C. 2 D. 4

OpenStudy (zephyr141):

i'm thinking that since it's further out by 4/1 the speed will also be 4/1 so i'm thinking he answer is 4?

OpenStudy (zephyr141):

@surry99

OpenStudy (surry99):

Hint: What are the forces acting on the satellite? There are two and they are equivalent.

OpenStudy (zephyr141):

gravity and acceleration?

OpenStudy (surry99):

gravitation (Newtons universal law of gravitation) and the centripetal force

OpenStudy (surry99):

Equate the two , then simplify and you will see the relationship between v and r.

OpenStudy (anonymous):

I think answer is C: 1) Formula distance[d]= velocity[V] . time[T] V=d/T 2) Time Do you remember Kepler's laws? \[\frac{ r _{1} ^{3} }{ r _{2}^{3} } = \frac{ T _{1} ^{2} }{ T _{2}^{2} }\] Lets say r1=1, r2=4 --> (T1/T2)^2 = 1/64 --> T1=1, T2=8 3)Orbit Distance = 2.pi.r 4) Let's put all these in formula V1 = 2.pi.r1 / T1 --> V1 = 2. pi .1 / 1 --> V1= 2pi V2 = 2.pi.r2 / T2 --> V2 = 2. pi .4 / 8 --> V2 = pi 5) Result: V1 / V2 = 2pi / pi = 2

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