satellites and orbits
if a new satellite is placed in a circular orbit at a distance of\[\left| r_2 \right|=4\left| r_1 \right|\]around the same planet what is the ratio\[\frac{v_1}{v_2}\]between the speed of the first satellite and the speed of the new satellite?
the choices are... A. (2)^(1/2) B. 1/[(2)^(1/2)] C. 2 D. 4
i'm thinking that since it's further out by 4/1 the speed will also be 4/1 so i'm thinking he answer is 4?
@surry99
Hint: What are the forces acting on the satellite? There are two and they are equivalent.
gravity and acceleration?
gravitation (Newtons universal law of gravitation) and the centripetal force
Equate the two , then simplify and you will see the relationship between v and r.
I think answer is C: 1) Formula distance[d]= velocity[V] . time[T] V=d/T 2) Time Do you remember Kepler's laws? \[\frac{ r _{1} ^{3} }{ r _{2}^{3} } = \frac{ T _{1} ^{2} }{ T _{2}^{2} }\] Lets say r1=1, r2=4 --> (T1/T2)^2 = 1/64 --> T1=1, T2=8 3)Orbit Distance = 2.pi.r 4) Let's put all these in formula V1 = 2.pi.r1 / T1 --> V1 = 2. pi .1 / 1 --> V1= 2pi V2 = 2.pi.r2 / T2 --> V2 = 2. pi .4 / 8 --> V2 = pi 5) Result: V1 / V2 = 2pi / pi = 2
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