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Mathematics 12 Online
OpenStudy (anonymous):

4x = -y. Find the constant of variation k for the direct variation.

OpenStudy (anonymous):

OpenStudy (anonymous):

@ganeshie8 do you think you could possibly help?

hartnn (hartnn):

direct variation is of the form y= kx so you just need to isolate y you can do that by multiplying both sides by -1

OpenStudy (anonymous):

Oh! I've been so confused as to where the k always comes! Thank you! Alright, so I just need to isolate y?? How did you get -1, though? O.o Is that just the general thing to use in this situation?

OpenStudy (anonymous):

Oh, and I got -4 when I multiplied the 4 by -1.

hartnn (hartnn):

k = -4 is correct :) and multiplying by -1 is not a general thing, i did it to isolate the 'y' note that y was multiplied by -1 to get +y, i multiplied -1 to -y

hartnn (hartnn):

if it were 6y = ... i would have divided both sides by 6 to get just y on left

OpenStudy (anonymous):

Oh..I think I get where the -1 came from. From what I think I remember, when there is something such as just a -y, there's basically an invisible 1 in front of the y, right? I think I recall learning something like that. And so the final answer is -4?

hartnn (hartnn):

yes, final answer is k =-4 :) \( y = 1 \times y\\ - y = -1 \times y \)

OpenStudy (anonymous):

Ohh, okay, thank you :)

hartnn (hartnn):

welcome ^_^

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