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Mathematics 11 Online
OpenStudy (anonymous):

A six-sided die of unknown bias is rolled 20 times, and the number 3 comes up 6 times. In the next three rounds (the die is rolled 20 times in each round), the number 3 comes up 6 times, 5 times, and 7 times. The experimental probability of rolling a 3 is __% which is approximately ___% more than its theoretical probability. (Round off your answers to the nearest integer.)

OpenStudy (perl):

so for the first 20 trials, 3 came up 6 times. what is the percentage there

OpenStudy (anonymous):

Im not exactly sure how to find the percentage of that

OpenStudy (perl):

i think we should do the total number of times 3 appears , and divide that by the total number of trials

OpenStudy (anonymous):

so 24/20?

OpenStudy (perl):

how many times does 3 appear total , in all the trials

OpenStudy (anonymous):

24

OpenStudy (perl):

correct

OpenStudy (perl):

and how many times did you roll the die in all

OpenStudy (anonymous):

80

OpenStudy (perl):

so the experimental prob. is # favorable / # total

OpenStudy (anonymous):

24 divided by 80?

OpenStudy (perl):

that will be a decimal, and how do we change a decimal to percent

OpenStudy (anonymous):

would it be 30 %?

OpenStudy (perl):

correct

OpenStudy (perl):

so thats your experimental probability, what about theoretical probability

OpenStudy (perl):

When we do theoretical probability, we can assume each possible event is equally likely.

OpenStudy (anonymous):

what does that mean

OpenStudy (perl):

when you throw a die, even before you throw it, you know there are 6 possibilities { 1, 2, 3, 4, 5, 6 }

OpenStudy (perl):

the chances of getting a 1 is the same as the chances of getting a 2 , etc

OpenStudy (perl):

there are 6 possibilities, how many ways can 3 occur?

OpenStudy (anonymous):

6?

OpenStudy (anonymous):

I think?

OpenStudy (perl):

1 way

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