A six-sided die of unknown bias is rolled 20 times, and the number 3 comes up 6 times. In the next three rounds (the die is rolled 20 times in each round), the number 3 comes up 6 times, 5 times, and 7 times. The experimental probability of rolling a 3 is __% which is approximately ___% more than its theoretical probability. (Round off your answers to the nearest integer.)
so for the first 20 trials, 3 came up 6 times. what is the percentage there
Im not exactly sure how to find the percentage of that
i think we should do the total number of times 3 appears , and divide that by the total number of trials
so 24/20?
how many times does 3 appear total , in all the trials
24
correct
and how many times did you roll the die in all
80
so the experimental prob. is # favorable / # total
24 divided by 80?
that will be a decimal, and how do we change a decimal to percent
would it be 30 %?
correct
so thats your experimental probability, what about theoretical probability
When we do theoretical probability, we can assume each possible event is equally likely.
what does that mean
when you throw a die, even before you throw it, you know there are 6 possibilities { 1, 2, 3, 4, 5, 6 }
the chances of getting a 1 is the same as the chances of getting a 2 , etc
there are 6 possibilities, how many ways can 3 occur?
6?
I think?
1 way
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