so x+2=y 2x=y+3 and you plug in x+2 in the 2x so2(x+2)=y+3 2x+4=y+3 how would you solve this problem
that doesnt seem right, 2+x would not simplify to 2x. 2x is 2 times x
im getting confuse
how can you solve it @J-bird
well, are you trying to solve for x or y??
yes
o,o
i said x OR y
butyou would have to plug in something @J-bird
Hello, This is what we call a system of equations. Note your equations are: \(x+2=y\) \(2x=y+3\) To start to solve the system, choose which variable to solve for. In our case that would be \(x\) since one of the equations is set to \(y\). \(x+2=y\) \(\Rightarrow 2x=\color{green}{(x+2)}+3\) Do you follow so far?
yes @Algorithmic
So can you continue from where I left of at?
i can try @Algorithmic
Okay try, from where I left off.
so you would have to put the 2 on the other side of the number @Algorithmic
Well first let us condense (combine likes terms) in our equation. \[2x = x + 5\] Did you see how I did that?
you added 3+2 right
Correct, now to isolate variable \(x\). \[2x = x + 5\] \[\Rightarrow 2x - x = 5\] \[\Rightarrow x = 5\] Do you understand?
i think i understand a lil bit @Algorithmic
Okay, so we know now that \(x = 5\). We can now use that in our first equation to get \(y\). \[x + 2 = y\] \[\Rightarrow 5 + 2 = y\]
so plug in 5 in the x
Correct, and you get \(y\). So now you have both the values for \(x\) and \(y\).
thanks a lot and do you have a kik
You are welcome. No I do not have a Kik.
ok
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