Use F=ma to explain why more massive objects accelerate at the same rate as less massive objects? More massive objects fall faster because gravity pulls on them harder. In F=ma, the force of gravity is the same for all objects. More massive objects require more force to accelerate at the same rate as less massive objects. In F=ma, if the acceleration is the same, but the mass goes up, then the force has to go up too Less massive objects must fall slower because in F=ma, air resistance is a smaller force that makes things fall together.
the last option is: Gravity is the same for all objects so F=ma does not matter. i believe it is the last option. is that correct?
oh no, i take it back. the second option maybe?
The correct answer is the second one, because all the objects have the same acceleration when they fall in the earth aproximately
thank you :) could i ask another question? this is the last one.
sure
The formula for KE = ½mv2. The formula for PE = mgh. If the mass of an object doubles, then the KE of that object should ________. double triple quadruple not change
would it double ?
\[K_i= \frac{ 1 }{ 2 }m_Iv ^{2}\]now if \[m_f=2m_i \rightarrow K_f=\frac{ 1 }{2 }m_fv ^{2}= \frac{ 1 }{ 2 }(2m_i)v ^{2}=2(\frac{ 1 }{ 2 }m_{i}v ^{2})\rightarrow 2K_i\]
so it would be the double
ahhh thank you!!
i get it now!
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