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Calculus1 14 Online
OpenStudy (anonymous):

Let S be the part of the surface z = 16 − (x^2 + y^2)^2 above the xy-plane, oriented upward. Let D be the disk in the xy-plane given by x^2 + y^2 ≤ 4 , oriented upward. Let F = yz i  + xz j  + (−11 + xy) k  (a) Compute divF= (b) Compute integral _D F · dA = (c) Compute integral_S F · dA=

OpenStudy (anonymous):

here I got the divf = 0 but I dont know how to get the integral _ D F * DA= if the divf is zero, Do i just need the volume of the disk?

OpenStudy (anonymous):

@ganeshie8 can you help me please

ganeshie8 (ganeshie8):

div(F) = 0 so the flux through any closed surface is 0

ganeshie8 (ganeshie8):

for part b, you want to set up a flux integral through the disk in xy plane

OpenStudy (anonymous):

thanks @ganeshie8 what about part c?

ganeshie8 (ganeshie8):

its just algebra, you have below : total flux out of closed surface = 0 flux out of bottom disk = -44pi so flux out of top surface = ?

OpenStudy (anonymous):

-44pi

OpenStudy (anonymous):

it has to be the same flux going in and going out right?

ganeshie8 (ganeshie8):

total flux out of closed surface = flux out of disk + flux out of top surface

ganeshie8 (ganeshie8):

0 = -44pi + flux out of top surface

ganeshie8 (ganeshie8):

flux out of top surface = ?

OpenStudy (anonymous):

divergent thm right? :)

OpenStudy (anonymous):

weird is marking -44pi right and not 44pi

ganeshie8 (ganeshie8):

-44pi for part b +44pi for part c

OpenStudy (anonymous):

for part c is marking -44pi right.. weird

OpenStudy (anonymous):

but i guess its because if negative flux its going in negative flux has to come out

ganeshie8 (ganeshie8):

not sure, they need to add up to 0

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