Question

what are the zeros of 16x^4 -1

Answer 1

Use the difference of squares rule to factor the left side
\[\Large 16x^4 -1 = 0\]
\[\Large (4x^2)^2 - (1)^2 = 0\]
\[\Large (4x^2-1)(4x^2+1) = 0\]
\[\Large ((2x)^2-(1)^2)(4x^2+1) = 0\]
\[\Large (2x-1)(2x+1)(4x^2+1) = 0\]
I'll let you finish up.

Answer 2

still don't get it, thanks though

Answer 3

you then set each factor equal to 0

Answer 4

so you'll have these equations

2x-1 = 0
2x+1 = 0
4x^2+1 = 0

solve each for x