Question

Find the coordinates of the points of intersection for the graphs of x^2+2y^2=20 and y=x-2.

Answer 1

Since y=x-2, we can replace every 'y' in the first equation with x-2. This is because the two are equivalent or the same.

So we get this...

\[\Large x^2+2y^2=20\]

\[\Large x^2+2(x-2)^2=20\]

\[\Large x^2+2(x^2-4x+4)=20\]

\[\Large x^2+2x^2-8x+8=20\]

I'll let you finish