Question

What is the equation of the line that passes through (–2, –3) and is perpendicular to 2x – 3y = 6?

Answer 1

First put the given equation into Y=mX+b form

Answer 2

take the negative reciprical of the slope m to find the Perpendicular Slope

Answer 3

how do i do that

Answer 4

ok we will walk through it

Answer 5

ok

Answer 6

2x - 3y = 6 solve for y

Answer 7

+3y to both sides?

Answer 8

3y = 2x - 6

y = (2/3)x - 2

Answer 9

The slope of that line is 2/3

Answer 10

how ddid you get from -6 to -2

Answer 11

divide everything by 3

Answer 12

oh ok

Answer 13

so the slope of the given line is m = 2/3

Answer 14

but thats none of my answer choics

Answer 15

key point:

the slope of a line perpendicular to a given line is

flip the slope over and put a negative on it

m=-3/2

Answer 16

oh!

Answer 17

well i found the answer then

Answer 18

now use that slope and the given point (-2,-3) for the line perpendicular

Answer 19

-3/2x-6

Answer 20

y-y1 = m(x-x1)

m=-3/2
(x1,y1) = (-2,-3)

Answer 21

y+3 = (-3/2)*(x+2)

Answer 22

Thank you mr DanJS

Answer 23

help me with another one?

Answer 24

y+ 3 = (-3/2)x -3

y = (-3/2)x - 6

Answer 25

sure, just remember a perpendicular slope is found by taking the negative reciprical,

if m = 4/5 then the perpendicular slope is -5/4

Answer 26

open a new thread and tag me for another question