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Mathematics 13 Online
OpenStudy (anonymous):

Find the binomial raised to the power, whose expansion it came from: 10a^3b^2

OpenStudy (sleepyjess):

I will tag some users that may be able to help. @Jhannybean @jim_thompson5910 @Callisto

jimthompson5910 (jim_thompson5910):

That's all it asks? Or is there more info?

OpenStudy (anonymous):

thats all it asks.

jimthompson5910 (jim_thompson5910):

what is the sum of the exponents?

OpenStudy (anonymous):

i dont know how to do this , can you explain it to me ?

jimthompson5910 (jim_thompson5910):

do you see the exponents?

OpenStudy (anonymous):

would it be 6 ?

jimthompson5910 (jim_thompson5910):

3+2 is not 6

OpenStudy (anonymous):

i multiplied them .

OpenStudy (anonymous):

but 5

jimthompson5910 (jim_thompson5910):

so we know that we have something in the form (x+y)^5

jimthompson5910 (jim_thompson5910):

look at pascal's triangle and look for the row that has 1, 5, etc etc

OpenStudy (anonymous):

1 5 10 10 5 1

jimthompson5910 (jim_thompson5910):

if 'a' is part of the x term in (x+y)^5, then that means we look at the 3rd number in that row of 1, 5, 10, 10, 5, 1 notice the third number is 10 and how there is a 10 as the coefficient of 10a^3b^2

jimthompson5910 (jim_thompson5910):

so that means the two terms x and y must have coefficients of 1 to make 10x^3*y^2 be equal to 10a^3b^2 In this case, x = a and y = b so we have (a+b)^5

OpenStudy (anonymous):

so (1+1)^5 ??????

jimthompson5910 (jim_thompson5910):

if you expanded out (a+b)^5, you would get a^5+5a^4b+10a^3b^2+10a^2b^3+5ab^4+b^5 and we can see the third term is 10a^3b^2

jimthompson5910 (jim_thompson5910):

no, (a+b)^5

OpenStudy (anonymous):

oh , okay . so where did 'a' come from?

jimthompson5910 (jim_thompson5910):

from 10a^3b^2

OpenStudy (anonymous):

right. thanks. i appreciate it.

jimthompson5910 (jim_thompson5910):

you're welcome

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