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OpenStudy (jhannybean):
solving for x instead?
OpenStudy (anonymous):
Yes
OpenStudy (jhannybean):
You want to isolate the x, to "undo" the cube, you have to take the cube root of both sides. Can you tell me what you can?
OpenStudy (jhannybean):
what you get*
OpenStudy (anonymous):
What would taking the cube of both sides look like though?
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OpenStudy (jhannybean):
\[\large \sqrt[3]{V} = \sqrt[3]{x^3}\]
OpenStudy (jhannybean):
When you take the cube root of x, it turns into : \[(x^3)^{1/3} = x^{3 \cdot 1/3}\]
OpenStudy (jhannybean):
and what is \[3 \cdot \frac{1}{3}\]
OpenStudy (anonymous):
1
OpenStudy (jhannybean):
Good :)
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OpenStudy (jhannybean):
So what would be your answer?
OpenStudy (anonymous):
I'm honestly still confused. Would it be just the 3 square root V?
OpenStudy (jhannybean):
Yes it would :)
OpenStudy (jhannybean):
What's confusing you?
OpenStudy (jhannybean):
Basically, if we are given an equation ans we are solving for one variable in place of the other, we want to "isolate" the variable we are solving for.
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OpenStudy (jhannybean):
In this case, x was raised to the power of 3, so we had to "undo" its power to get it all by itself.
OpenStudy (jhannybean):
and the only way to "undo" \(x^3\) is to take it's inverse power, which is \(\large \sqrt[3]{x}\)
OpenStudy (anonymous):
Ohhh ok, I was confused about the x part, but now I get it... I have one more problem, can you help me with it?
OpenStudy (jhannybean):
And that is why you got x o the power of 1, because \(3 \cdot \frac{1}{3} = 1\)
OpenStudy (jhannybean):
Sure thing :)
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OpenStudy (anonymous):
Thank you! So the square root of a^2+b^2=c
OpenStudy (anonymous):
And we are solving for a
OpenStudy (jhannybean):
Ok, you want to isolate a^2 on the left side of the equation first, how would you do that?
OpenStudy (anonymous):
Wouldn't you square both sides first to get rid of the square root?
OpenStudy (jhannybean):
Nope, that would make the left side more complicated to solve than need be, try again :P
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OpenStudy (anonymous):
Subtract b^2?
OpenStudy (jhannybean):
Good :)
OpenStudy (jhannybean):
And what do you get?
OpenStudy (anonymous):
a^2=c^2-b^2
OpenStudy (jhannybean):
Good:)
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OpenStudy (jhannybean):
Now you can take the square root of both sides, just like your previous problem, "undo" the square on a^2.
OpenStudy (anonymous):
Wait, was I supposed to have c^2?
OpenStudy (jhannybean):
oh no, you don't need to square that. You just leave the c term as i is.
OpenStudy (jhannybean):
it*
OpenStudy (anonymous):
So would it be a=square root of c-b^2, or would you take the b^2 out?
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