a dog heading due north at a constant speed of 2 meters per second trots past a fire hydrant at t=0 sec. Another dog heading due east at a constant speed of 3 meters per second runs by the hydrant at t=1 sec. At t=9 sec, the rate of change in the distance between the two dogs is?

Question

anonymous · Answer

I am completely lost!

anonymous · Answer

Make a graph of the two dogs paths. With time on the x-axis and distance from the fire hydrant on the y-axis subtract the two lines to get a third. Take the derivative of that third line and find the value at t=9